3600=2x^2

Solution for 3600=2x^2 equation:

3600=2x^2

We move all terms to the left:

3600-(2x^2)=0

a = -2; b = 0; c = +3600;
Δ = b2-4ac
Δ = 02-4·(-2)·3600
Δ = 28800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28800}=\sqrt{14400*2}=\sqrt{14400}*\sqrt{2}=120\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{2}}{2*-2}=\frac{0-120\sqrt{2}}{-4}
=-\frac{120\sqrt{2}}{-4}
=-\frac{30\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{2}}{2*-2}=\frac{0+120\sqrt{2}}{-4}
=\frac{120\sqrt{2}}{-4}
=\frac{30\sqrt{2}}{-1}
$